![]() If the tonal values are not included in the source data (RAW file), they will not "be created" when converting to 32 bits. How can you have more color tonal values than the camera actually supplies? To take my question one step deeper technically, if the camera only saves the color senor values as 12 or 14 bits of color tonal values how can you end up with 32bits of color value. My question is if the RAW file contains 16bits of color tonal values and the file is opened in the Develop Persona do you then have 16bits of color tonal values or is it translated to 32bits of color tonal values. I understand that Develop Persona is 32bits. See also: Should you raise Bit Depth and Color Space before Color Grading? So the whole is finally more a mathematical and algorithmic procedure, aka to map certain color values from a smaller gamut into a bigger working one. ![]() ![]() And even if they would, the human eye isn't capable of seeing all those different colors. Images don't contain all technical possible available colors, just portions of those. Also keep in mind that not all possible theoretical colors of a color space (gamut) are really used/available in a certain RAW image (a shot photo scene). With other words, the cams color values do all fit easily in the wider color space here. Thus the 16-bit color values of the cam are streched over/inside a much greater breadth of the target working 32-bit gamut. The working color space (gamut) of let's say ProPhoto, so a very wide all-encompassing color profile, is guaranteed to be wider than both the monitor (sRGB, or AdobeRGB for pro models) and the camera color space (gamut). ![]() ![]()
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